y-1=1/4(x-3)^2

Solution for y-1=1/4(x-3)^2 equation:

x in (-oo:+oo)

y-1 = (1/4)*(x-3)^2 // - (1/4)*(x-3)^2

y-((1/4)*(x-3)^2)-1 = 0

(-1/4)*(x-3)^2+y-1 = 0

y-1/4*(x-3)^2-1 = 0

y-1/4*(x-3)^2-1 = 0

3/2*x-1/4*x^2+y-9/4-1 = 0

3/2*x-1/4*x^2+y-13/4 = 0

3/2*x-1/4*x^2+y-13/4 = 0

3/2*x-1/4*x^2+y-13/4 = 0

DELTA = (3/2)^2-(-1/4*4*(y-13/4))

DELTA = y-1

y-1 = 0

y-1 = 0 // + 1

y = 1

DELTA = 0  <=>  t_3 = 1

x = -3/2/(-1/4*2) i y = 1

x = 3 i y = 1

( x = ((y-1)^(1/2)-3/2)/(-1/4*2) or x = (-(y-1)^(1/2)-3/2)/(-1/4*2) ) i y > 1

( x = -2*((y-1)^(1/2)-3/2) or x = 2*((y-1)^(1/2)+3/2) ) i y > 1

y-1 > 0

y-1 > 0 // + 1

y > 1

x in { 3, -2*((y-1)^(1/2)-3/2), 2*((y-1)^(1/2)+3/2) }